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Voltage and dbm formula

Created: Nov 23, 2020 22:07:24Latest reply: Jul 3, 2021 07:36:03 1285 23 0 0 0
  Rewarded HiCoins: 0 (problem resolved)
Hi friends,
Can anyone help to get formula for RSL (voltage and dbm) which used during alignment process.

Featured Answers
ahXing
Created Nov 24, 2020 12:00:27

(sorry - something went wrong while pasting)

Y = 15.9 x X - 91.6   <- this is the equation you've asked for.


You can check it:
X = 2.5 =>
Y = 15.9 x 2.5 - 91.6 = -51.85 (which corresponds with graphic)


double check:
X = 3.5 =>
Y = 15.9 x 2.5 - 91.6 = -36 (also correct according to graphic)  


So, with a RSSI voltage on port of 3.5 Volt, the RSL is around -36 dBm


Your question:

"if we have on multimeter during alignment 3V ,what's corresponding in dbm ?"

X = 3 =>
Y = 15.9 x 3 - 91.6 = - 43.6 dBm (which is also according to graphic)   i_f48.gif



Best Regards


ahXing

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user_4034933
user_4034933 Created Nov 24, 2020 13:01:16 (0) (0)
Thanks for your effort  

Recommended answer

BetterMing
Created Nov 24, 2020 07:06:16

Hello, dear.

Are you looking for this formula?

RTN XMC

For more information, you can refer to the following materials.

https://support.huawei.com/enterprise/en/doc/EDOC1100052171?idPath=9884302|23708646|9858638|22318679|16321

Thanks!

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user_4034933
user_4034933 Created Nov 24, 2020 07:49:45 (0) (0)
Thanks for sharing that,
But any equation there between voltage and dbm?  
ahXing
ahXing Reply user_4034933  Created Nov 24, 2020 11:52:11 (0) (0)
Dear user_4034933,

You could derive the equation like this: Y = 15.9 x X - 91.6

Suppose:
X = RSSI port voltage
Y = RSL (in dBm)

then:
Y = aX +b
-90 = a(0.1) + b
-20 = a(4.5) + b
               b = -20 - a(4.5)
-90 = a(0.1) + [-20 - a(4.5)]
-90 = a(0.1) -20 - a(4.5)
     -a(4.4) = -90 + 20
     -a(4.4) = -70
      a      =  70/4.4 = 15.9
               b = -20 - a(4.5) ->
               b = -20 - 15.9*(4.5)
               b = -20 - 71.  
All Answers
Hello User. we are reviewing your question and we will answer you shortly. Thanks.
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Hello, dear.
What is formula RSL? Received signal level(RSL)?
Can you describe your problem in more detail?
Thanks!
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user_4034933
user_4034933 Created Nov 24, 2020 06:53:27 (0) (0)
Need formula between voltage received in multimeter and received RSL in dbm.
for example:-
if we have on multimeter during alignment 3V ,what's corresponding in dbm ?  

Hello, dear.

Are you looking for this formula?

RTN XMC

For more information, you can refer to the following materials.

https://support.huawei.com/enterprise/en/doc/EDOC1100052171?idPath=9884302|23708646|9858638|22318679|16321

Thanks!

View more
  • x
  • convention:

user_4034933
user_4034933 Created Nov 24, 2020 07:49:45 (0) (0)
Thanks for sharing that,
But any equation there between voltage and dbm?  
ahXing
ahXing Reply user_4034933  Created Nov 24, 2020 11:52:11 (0) (0)
Dear user_4034933,

You could derive the equation like this: Y = 15.9 x X - 91.6

Suppose:
X = RSSI port voltage
Y = RSL (in dBm)

then:
Y = aX +b
-90 = a(0.1) + b
-20 = a(4.5) + b
               b = -20 - a(4.5)
-90 = a(0.1) + [-20 - a(4.5)]
-90 = a(0.1) -20 - a(4.5)
     -a(4.4) = -90 + 20
     -a(4.4) = -70
      a      =  70/4.4 = 15.9
               b = -20 - a(4.5) ->
               b = -20 - 15.9*(4.5)
               b = -20 - 71.  

(sorry - something went wrong while pasting)

Y = 15.9 x X - 91.6   <- this is the equation you've asked for.


You can check it:
X = 2.5 =>
Y = 15.9 x 2.5 - 91.6 = -51.85 (which corresponds with graphic)


double check:
X = 3.5 =>
Y = 15.9 x 2.5 - 91.6 = -36 (also correct according to graphic)  


So, with a RSSI voltage on port of 3.5 Volt, the RSL is around -36 dBm


Your question:

"if we have on multimeter during alignment 3V ,what's corresponding in dbm ?"

X = 3 =>
Y = 15.9 x 3 - 91.6 = - 43.6 dBm (which is also according to graphic)   i_f48.gif



Best Regards


ahXing

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user_4034933
user_4034933 Created Nov 24, 2020 13:01:16 (0) (0)
Thanks for your effort  
But I think there's standard equation for that
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user_4034933  wrote:
"But I think there's standard equation for that"


Yes, there is... which is:

dBm_voltage

and R, is the impedance (in radio systems = 50 Ω ; television and video systems = 75 Ω ). For calibrations however not suitable, because of the way how RSSI is being derived. Especially nowadays, with modern fast changing complex digital signals... the averaging of the signal power can cause for dramatic misjudgements. Therefore, this value is rectified, filtered and processed (implementation dependent, mostly at IF stage). So, for calibration - stick to the tables and diagrams provided for that device.

Another reason why this equation is unsuitable for Rx calibration: please realize, you are not measuring the voltage at antenna port, but way back (at IF probably) - after the filters and amplifiers.


Hope this helps.


ahXing

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user_4034933
user_4034933 Created Nov 24, 2020 16:14:37 (0) (0)
Thanks for support  
[RSL(dbm) +120] / 40 ...

The result is a value RSL(V)....

EX..
We want to convert -75dbm to RSL(V) :
{-75 +120} / 40 = 1.12V
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user_4034933
user_4034933 Created Nov 24, 2020 14:22:59 (0) (0)
Thanks friend  
user_4096263
user_4096263 Created Jan 9, 2021 13:05:06 (0) (0)
120 & 40 values for what ?  
Thanks all for great support
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RSL+120/40 =VDC
For example RSL= -45 dBm

V = -45 + 120 / 40
V= 1.875 VDC
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user_4034933
user_4034933 Created Nov 25, 2020 14:40:27 (0) (0)
Thanks for your support  
user_4096263
user_4096263 Created Jan 9, 2021 13:03:18 (0) (0)
120 & 40 values for what ?  
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