storage

Zhouyu · Created Nov 15, 2018 02:23:33

Hello,dear,

The resolutions of video surveillance images include CIF, D1, 720P, and 1080P. These resolutions have typical bit rates such as 512Kbps, 1 Mbit/s, 2 Mbit/s, 4 Mbit/s, and 8 Mbit/s. In fact, regardless of the analog image or digital image, the video storage space is calculated based on the bit rate, which is not related to the resolution.

The storage capacity is calculated based on the bit rate. The formula for calculating the storage capacity is as follows:

1 hour storage capacity of a camera with the bit rate of n (unit: Mbit/s) =[(n/8) *3600]/1024 GB

Formula parsing:

n Mbps/8 Conversion unit: n MBps

n MBps*3600 Calculate the storage capacity in one hour (unit: MB).

n *3600/1024 The unit is GB.

The following provides an example to describe how to calculate the raw capacity required for storing video images. Assume that there are 100 channels of 720p IPC, the storage bit rate is set to 2 Mbit/s, and all day recording is required. The storage duration is 30 days.

The calculation process is as follows:

(1) First, calculate the raw storage capacity required by a single video every day.

[2Mb/s*3600s/h*24h]/8=21.1GB

(2) Calculate the raw storage capacity required by a single video for 30 days.

[2Mb/s*3600s/h*24h]/8*30=633GB

(3) Finally, calculate the raw storage capacity of 100 channels of videos in 30 days.

[2Mb/s*3600s/h*24h]/8*30*100=63300GB/1024=61.8T

chouhao · Created Nov 14, 2018 02:31:37

Hello, bro,

wish you can consider my answer.
the formula is like below:
storage(MB)=IPC Bit rate(Mbps) * time (days) * 24*3600/8
so for your project, per camera has 500G. while based on the experience, 1M 1 camera 1 day is 11G.
so days≈500G/11G=45day. if you change the settings from 1M to 512. it`s possible.

Yoge · Created Nov 14, 2018 02:48:10

Hello, the formula used to calculate the storage capacity is as below

Storage Space (GB) = Bitrate (Kbps) * 1000/8 * 3600 * 24 * Cameras * Days/1000 000 000

*1000/8 = to convert kbps to Bytes
*3600 = to convert from seconds to hour
*24 = to convert from hour to day
Cameras = total number of cameras
Days = total number of days you want to record

In this case we assume if bit rate is 1024kbps

Storage Space (GB) = 1204 (Kbps) * 1000/8 * 3600 * 24 * 8 * 60/1000 000 000 =

5,308.416GB or 5.308416 TB

This based on 24 hrs non-stop recording, you can try to lower the bit rate of the recording to achieve 60 days recording based on 4 TB

wangjun188 · Created Nov 14, 2018 07:50:51

hello,bro! Hoping you are fine and wish you consider my answer:
Different bit rate for camera needs different storage. You can calculate the bit rate refer to below:
4*1024*1024*8/60/24/3600/8=809kpbs, so if the camera bit rate is less than 809kpbs, 4T storage is enough for 8 cameras to storage the vedio 60 days.

Zhouyu · Created Nov 15, 2018 02:23:33

Hello,dear,

The resolutions of video surveillance images include CIF, D1, 720P, and 1080P. These resolutions have typical bit rates such as 512Kbps, 1 Mbit/s, 2 Mbit/s, 4 Mbit/s, and 8 Mbit/s. In fact, regardless of the analog image or digital image, the video storage space is calculated based on the bit rate, which is not related to the resolution.

The storage capacity is calculated based on the bit rate. The formula for calculating the storage capacity is as follows:

1 hour storage capacity of a camera with the bit rate of n (unit: Mbit/s) =[(n/8) *3600]/1024 GB

Formula parsing:

n Mbps/8 Conversion unit: n MBps

n MBps*3600 Calculate the storage capacity in one hour (unit: MB).

n *3600/1024 The unit is GB.

The following provides an example to describe how to calculate the raw capacity required for storing video images. Assume that there are 100 channels of 720p IPC, the storage bit rate is set to 2 Mbit/s, and all day recording is required. The storage duration is 30 days.

The calculation process is as follows:

(1) First, calculate the raw storage capacity required by a single video every day.

[2Mb/s*3600s/h*24h]/8=21.1GB

(2) Calculate the raw storage capacity required by a single video for 30 days.

[2Mb/s*3600s/h*24h]/8*30=633GB

(3) Finally, calculate the raw storage capacity of 100 channels of videos in 30 days.

[2Mb/s*3600s/h*24h]/8*30*100=63300GB/1024=61.8T

LemonLove · Created Nov 15, 2018 03:21:42

HI，bro:
1.Please confirm the transmission rate of the camera,the default is 4Mbps.we can check it on the IVS client.Device>>choesen camera(double click)>>Video Encoding settings>>Bit rate.
2.Please confirm the recording plan situation.we can check it on the IVS clien.Video>>server Recording >>Chosen camera>>check the recording plan.
3.Please check the actual available space on the hard drive.we can check it on the server web page.login the OMU portal >>chosen storage.
for example:
the camera use the default bit,and set the recording plan for all day.
The storage of a camera for one day is:
4Mbps*60*60*24/8=43GB.
So the storage of 8 cameras a day is:
43GB*8=344GB.
In this case, the capacity of 4T cannot be stored for 60 days. It is recommended to reduce the transmission rate or set the schedule to store only important time.

Nicholas.Guldan.Lee · Created Nov 21, 2018 01:59:49

here is the Calculation
*1000/8 = to convert kbps to Bytes
*3600 = to convert from seconds to hour
*24 = to convert from hour to day
Cameras = total number of cameras
Days = total number of days you want to record

assume if bit rate is 1024kbps

Storage Space (GB) = 1204 (Kbps) * 1000/8 * 3600 * 24 * 8 * 60/1000 000 000 =

5,308.416GB or 5.308416 TB

so the bit rate must lower than 1024kbps

chenjun108 · Created Nov 21, 2018 02:33:10

Hi, brother! Wish you can consider my solution
Different bit rate for camera needs different storage. You can calculate the bit rate refer to below:
4*1024*1024*8/60/24/3600/8=809kpbs, so if the camera bit rate is less than 809kpbs, 4T storage is enough for 8 cameras to storage the vedio 60 days.

storage

Best answer

Third Party’s Trade Secret

My Followers

Enterprise

Consumer

Corporate

Carriers

storage

Best answer

Third Party’s Trade Secret

My Followers