Hello,
R1 cannot access R6. After the packet reaches R2, R2 iterates the next hop to 5.5.5.5 based on the routing table. Then, find the FIB table according to 5.5.5.5. In the FIB, there is only one route to 5.5.5.5, that is, 5.5.5.0/24. However, this route has no available label. Therefore, the data packets sent from R2 to R3 are in the form of IP packets. After receiving the data packets, R3 has no corresponding route (no BGP route) to the destination and discards the data packets.