How to video record storage space?

heshamk · Created Mar 31, 2019 09:27:47

The resolutions of video surveillance images include CIF, D1,720P, and 1080P. These resolutions have typical bit rates such as 512Kbps, 1Mbit/s, 2 Mbit/s, 4 Mbit/s, and 8 Mbit/s. In fact, regardless of the analogimage or digital image, the video storage space is calculated based on the bitrate, which is not related to the resolution.

The storage capacity is calculated based on the bit rate. The formula for calculating the storage capacity is as follows:

1 hour storage capacity of a camera with the bit rate of n (unit: Mbit/s)=[(n/8) *3600]/1024 GB

Formula parsing:

n Mbps/8 Conversion unit: n MBps
n MBps*3600 Calculate the storage capacity in one hour (unit: MB).
n *3600/1024 The unit is GB.

The following provides an example to describe how to calculatethe raw capacity required for storing video images. Assume that there are 100channels of 720p IPC, the storage bit rate is set to 2 Mbit/s, and all dayrecording is required. The storage duration is 30 days.

The calculation process is as follows:

(1) Firstly, calculate the raw storage capacity required by a single video everyday.

[2Mb/s*3600s/h*24h]/8=21.1GB

(2) Calculate the raw storage capacity required by a single video for 30 days.

[2Mb/s*3600s/h*24h]/8*30=633GB

(3) Finally, calculate the raw storage capacity of 100 channels of videos in 30days.

[2Mb/s*3600s/h*24h]/8*30*100=63300GB/1024=61.8T

heshamk · Created Mar 31, 2019 09:27:47

The resolutions of video surveillance images include CIF, D1,720P, and 1080P. These resolutions have typical bit rates such as 512Kbps, 1Mbit/s, 2 Mbit/s, 4 Mbit/s, and 8 Mbit/s. In fact, regardless of the analogimage or digital image, the video storage space is calculated based on the bitrate, which is not related to the resolution.

The storage capacity is calculated based on the bit rate. The formula for calculating the storage capacity is as follows:

1 hour storage capacity of a camera with the bit rate of n (unit: Mbit/s)=[(n/8) *3600]/1024 GB

Formula parsing:

n Mbps/8 Conversion unit: n MBps
n MBps*3600 Calculate the storage capacity in one hour (unit: MB).
n *3600/1024 The unit is GB.

The following provides an example to describe how to calculatethe raw capacity required for storing video images. Assume that there are 100channels of 720p IPC, the storage bit rate is set to 2 Mbit/s, and all dayrecording is required. The storage duration is 30 days.

The calculation process is as follows:

(1) Firstly, calculate the raw storage capacity required by a single video everyday.

[2Mb/s*3600s/h*24h]/8=21.1GB

(2) Calculate the raw storage capacity required by a single video for 30 days.

[2Mb/s*3600s/h*24h]/8*30=633GB

(3) Finally, calculate the raw storage capacity of 100 channels of videos in 30days.

[2Mb/s*3600s/h*24h]/8*30*100=63300GB/1024=61.8T

Mohamed_Ayed · Created Apr 5, 2019 08:47:35

thanks hesham good answer

How to video record storage space?

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