# Relationship between the optical power and OSNR of BWS 1600G and the split ratio of the MON port on an optical amplifier board

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The OSNR is proportional to the incident optical power. The split ratio of the MON port and OUT port on an OA board is 1:99. That is, the power of the MON port is 20 dB lower than that of the OUT port, which can be calculated as follows: Pout (dBm) �?Pmon (dBm) = 10 x l g (99/1) = 20 dB.

###### Other related questions:
Split ratio calculation for the MON port of the OAU board on OSN 6800
The split ratio between the MON port and the OUT port is 1:99. In other words, the optical power of the MON port is 20 dB lower than that of the OUT port, which is calculated using the following formula: Pout (dBm) �?Pmon (dBm) = 10 x lg(99/1) = 20 dB.

Nominal single-wavelength input optical power for OA boards on BWS 1600G?
Suggestion: What is the nominal single-wavelength input optical power is determined for OA boards of the BWS 1600G? Answer: Strictly speaking, there is no definition of nominal single-wavelength optical power for OA boards. The optical power is determined as follows: To increase the signal-to-noise ratio, the incident optical power and receive optical power must reach the maximum as possible. A 400G OAU board is used as an example. The maximum incident optical power is 20 dBm and 40 wavelengths are supported. Therefore, the maximum single-wavelength output optical power is 4 dBm. The BA gain is 19 dB, and therefore the single-wavelength input optical power of the BA board is defined to -15 dBm. A VOA and DCM need to be added between PA and BA boards, the minimum VOA attenuation is 3 dB, and the maximum DCM attenuation is 12 dBm. Therefore, the minimum single-wavelength output optical power of the PA board is as follows: -15 + 12 + 3 = 0 (dBm). The C-band gain is 20 dB and the L-band gain is 19 dB, and therefore the maximum single-wavelength input optical power of the PA board is -19 dBm. The attenuation of the maximum span is 36 dB, and therefore the minimum single-wavelength input optical power of the PA board is as follows: 4 - 36 = 32 (dBm). Varying with span reaches, the single-wavelength input optical power of the PA board ranges from -32 dBm to -19 dBm. The gain of a PA board embedded with a Raman amplifier (OAU_R) is 10 dB, and therefore the single-wavelength input optical power is -9 dBm.

Split ratio of MON ports on each board of LH DWDM devices
Question: What is the split ratio of MON ports on each board of LH DWDM devices? Analysis: None Answer: 1. The split ratio of MON ports on M32/D32/V32/M40/D40/V40 boards of each version is 1:10. (The MON ports have a 10 dB optical power difference with the main optical path.) 2. The split ratio of MON ports on OAU/OBU/OPU/WBA/WPA/WLA/RPC/RPA/RPL/FIU boards of each version is 1:99. (The MON ports have a 20 dB optical power difference with the main optical path.) 3. The split ratio of MON ports on HBA boards of each version is 1:999. (The MON ports have a 30 dB optical power difference with the main optical path.) Suggestion and conclusion: None

Optical power difference between the IN port of the D40 board and the OUT/MON port of the M40 board
The MON port of M40 board has 10 dB lower optical power than the IN port of the D40 board and the OUT port of the M40V board. The split ratio between the MON port and OUT port and that between the MON port and IN port are both 10:90. In other words, the optical power of the MON port is 10 dB lower than that of the IN port. The calculation formula is as follows: Optical power (dBm) of the IN port �?Optical power (dBm) of the MON port = 10 x lg(90/10) = 10 dB.

Split ratio of the MON port on the FIU board
For TN11FIU, TN12FIU, TN13FIU01, TN14FIU, and TN21FIU boards, the split ratio between the MON port and OUT port is 1:99. In other words, the optical power of the MON port is 20 dB lower than that of the OUT port, which can be calculated using the following formula: Optical power (dBm) of the OUT port �?Optical power (dBm) of the MON port = 10 x lg(99/1) = 20 dB. For the TN13FIU02 board, the split ratio between the MON port and OUT port is 0.1:99.9. In other words, the optical power of the MON port is 30 dB lower than that of the OUT port, which can be calculated using the following formula: Optical power (dBm) of the OUT port �?Optical power (dBm) of the MON port = 10 x lg(99.9/0.1) = 30 dB.

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