# SNR calculating

95
The SNR is calculated using the logarithm.

For example, the SNR of a signal is 30 dB when it traverses one OA. If the signal power is S and the noise is N, the signal power is 10lgS, and the noise power is 10lgN. Before the signal traverses the OA, the noise is low and is negligible. After the signal traverses the OA, the noise increases sharply to N. Therefore, the SNR changes sharply.

When the signal traverses the second OA, the SNR is: 10lgS/2N = 10lgS/N �?10lg2. When the signal traverses the third OA, the SNR is: 10lgS/3N = 10lgS/N �?10lg3.

The number of OAs determines how many times the noise N is multiplied.

Assume that the SNR is 20 dB when the signal traverses the tenth OA and that all OAs cause the same impact on the noise. At the first OA, the SNR is: 10lgS/N = 30.

At the second OA, the SNR is: 10lgS/2N = 10lgS/N �?10lg2 = 30 �?10lg2 = 27, and the change is 3.

At the third OA, the SNR is: 30 �?10lg3 = 25.2, and the change is 1.8.

At the fourth OA, the SNR is: 30 �?10lg4 = 24, and the change is 1.2.

At the fifth OA, the SNR is: 30 �?10lg5 = 23, and the change is 1.

At the sixth OA, the SNR is: 30 �?10lg6 = 22.2, and the change is 0.8.

At the seventh OA, the SNR is: 30 �?10lg7 = 21.5, and the change is 0.7.

At the eighth OA, the SNR is: 30 �?10lg8 = 21, and the change is 0.5.

At the ninth OA, the SNR is: 30 �?10lg9 = 20.4, and the change is 0.6.

At the tenth OA, the SNR is: 30 �?10lg10 = 20, and the change is 0.4.

The noise varies significantly according to the input optical power, gain, and OA model. An OA with higher noise has greater impact on the entire SNR.

###### Other related questions:

SNR calculating
The SNR is calculated using the logarithm.
For example, the SNR of a signal is 30 dB when it traverses one OA. If the signal power is S and the noise is N, the signal power is 10lgS, and the noise power is 10lgN. Before the signal traverses the OA, the noise is low and is negligible. After the signal traverses the OA, the noise increases sharply to N. Therefore, the SNR changes sharply.
When the signal traverses the second OA, the SNR is: 10lgS/2N = 10lgS/N �?10lg2. When the signal traverses the third OA, the SNR is: 10lgS/3N = 10lgS/N �?10lg3.
The number of OAs determines how many times the noise N is multiplied.
Assume that the SNR is 20 dB when the signal traverses the tenth OA and that all OAs cause the same impact on the noise. At the first OA, the SNR is: 10lgS/N = 30.
At the second OA, the SNR is: 10lgS/2N = 10lgS/N �?10lg2 = 30 �?10lg2 = 27, and the change is 3.
At the third OA, the SNR is: 30 �?10lg3 = 25.2, and the change is 1.8.
At the fourth OA, the SNR is: 30 �?10lg4 = 24, and the change is 1.2.
At the fifth OA, the SNR is: 30 �?10lg5 = 23, and the change is 1.
At the sixth OA, the SNR is: 30 �?10lg6 = 22.2, and the change is 0.8.
At the seventh OA, the SNR is: 30 �?10lg7 = 21.5, and the change is 0.7.
At the eighth OA, the SNR is: 30 �?10lg8 = 21, and the change is 0.5.
At the ninth OA, the SNR is: 30 �?10lg9 = 20.4, and the change is 0.6.
At the tenth OA, the SNR is: 30 �?10lg10 = 20, and the change is 0.4.
The noise varies significantly according to the input optical power, gain, and OA model. An OA with higher noise has greater impact on the entire SNR.

How do signal measurement tools calculate the SNR? Does a higher SNR value indicate a better signal quality
The SNR value obtained using a signal measurement tool is not the actual SNR on a network adapter. The tool obtains the SNR value by comparing the detected signal strength with a predefined noise value (-96 dBm for example). A high SNR value does not indicate a good signal quality because the high SNR may be caused by interference signals. The signal quality should be evaluated by the SNR and signal to interference ratio (SIR).

How to calculate the recording capacity
Recording data storage capacity = (Number of D1 recording channels x D1 bit rate x 3600 x 24 x Number of recording storage days + Number of 720p recording channels x 720p bit rate x 3600 x 24 x Number of recording storage days + Number of 1080p recording channels x 1080p bit rate x 3600 x 24 x Number of recording storage days)/8. In the case that the server storage capacity is fixed, if the number of recording channels is decreased and the recording bit rate is lowered, the number of recording storage days can be increased.

###### If you have more questions, you can seek help from following ways:

To iKnow
To Live Chat